Which value satisfies the equation 2x^2 - 3x - 2 = 0?

• A. 2
• B. 0
• C. 1
• D. -3

Answer: (A)

This question tests how to find the zeros of a quadratic by factoring. Look at the quadratic 2x^2 - 3x - 2 and factor it: 2x^2 - 3x - 2 = (2x + 1)(x - 2). When a product equals zero, each factor can be zero, giving potential solutions: 2x + 1 = 0 or x - 2 = 0, which yield x = -1/2 or x = 2.

Among the given options, the value 2 is the one that makes the equation true. You can check by substitution: 2(2)^2 - 3(2) - 2 = 8 - 6 - 2 = 0. The other values don’t satisfy the equation (for example, x = 0 gives -2).