Divide the polynomial x^3 - 6x^2 + 11x - 6 by (x - 2). What is the quotient?

Prepare for the TSI A2 Mathematics Test. Enhance your skills with comprehensive questions, detailed solutions, and effective strategies. Succeed on your exam!

Multiple Choice

Divide the polynomial x^3 - 6x^2 + 11x - 6 by (x - 2). What is the quotient?

Explanation:
Dividing by a binomial like x − 2 reduces the degree by one, so you expect a quadratic as the quotient. A quick method is synthetic division with the value 2. Bring down the leading coefficient 1. Then multiply by 2 and add successively: 1 stays, 1×2 = 2 added to −6 gives −4, −4×2 = −8 added to 11 gives 3, 3×2 = 6 added to −6 gives 0 remainder. The resulting coefficients are 1, −4, 3, so the quotient is x^2 − 4x + 3. You can also see this by factoring the cubic as (x−1)(x−2)(x−3); removing the (x−2) factor leaves (x−1)(x−3) = x^2 − 4x + 3, which matches the quotient.

Dividing by a binomial like x − 2 reduces the degree by one, so you expect a quadratic as the quotient. A quick method is synthetic division with the value 2. Bring down the leading coefficient 1. Then multiply by 2 and add successively: 1 stays, 1×2 = 2 added to −6 gives −4, −4×2 = −8 added to 11 gives 3, 3×2 = 6 added to −6 gives 0 remainder. The resulting coefficients are 1, −4, 3, so the quotient is x^2 − 4x + 3. You can also see this by factoring the cubic as (x−1)(x−2)(x−3); removing the (x−2) factor leaves (x−1)(x−3) = x^2 − 4x + 3, which matches the quotient.

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy